A $300 m$ long wire is used to fence a rectangle plot whose length is twice its width. find the length and width.

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Solution

$\begin{matrix} f e n s e = 300 m p e r i m e t e r = 300 m 2 (l + b) = 300 2 (2 x + x) = 300 3 x = 150 x = 50 ∴ w i d t h = 50 m, a n d l e n g t h 2 x = 2 \times 50 = 100 m . \end{matrix}$

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A 300 m long wire is used to fence a rectangle plot whose length is twice its width. find the length and width.

fense=300mperimeter=300m2(l+b)=3002(2x+x)=3003x=150x=50∴width=50m,andlength2x=2×50=100m.

A $300 m$ long wire is used to fence a rectangle plot whose length is twice its width. find the length and width.

$\begin{matrix} f e n s e = 300 m p e r i m e t e r = 300 m 2 (l + b) = 300 2 (2 x + x) = 300 3 x = 150 x = 50 ∴ w i d t h = 50 m, a n d l e n g t h 2 x = 2 \times 50 = 100 m . \end{matrix}$