A 300 - resistor and a capacitor of 25- - F are connected in series to a 200 V - 50 Hz ac source- The current in the circuit is

I=VZ Z for series RC circuit Z=√(R^2+ ( 1ω C )^2) =√((300)^2+(400)^2)=500 Ω i=200500=0.4 A ...

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Standard XII

Physics

RLC Circuit

A 300 Ω resis...

Question

A $300$ $Ω$ resistor and a capacitor of $(\frac{25}{π}) μ F$ are connected in series to a $200 V$ – $50 Hz$ ac source. The current in the circuit is

0.4 A

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0.8 A

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0.6 A

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0.1 A

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Solution

The correct option is A $0.4 A$
$i = \frac{V}{Z}$

$Z$ for series RC circuit

$Z = \sqrt{R^{2} + {(\frac{1}{ω C})}^{2}}$

$= \sqrt{(300)^{2} + (400)^{2}} = 500 Ω$

$i = \frac{200}{500} = 0.4 A$

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A 300 Ω resistor and a capacitor of (25π)μF are connected in series to a 200 V – 50 Hz ac source. The current in the circuit is

The correct option is A 0.4 Ai=VZ Z for series RC circuit Z=√R2+(1ωC)2 =√(300)2+(400)2=500 Ω i=200500=0.4 A

A $300$ $Ω$ resistor and a capacitor of $(\frac{25}{π}) μ F$ are connected in series to a $200 V$ – $50 Hz$ ac source. The current in the circuit is

The correct option is A $0.4 A$
$i = \frac{V}{Z}$

$Z$ for series RC circuit

$Z = \sqrt{R^{2} + {(\frac{1}{ω C})}^{2}}$

$= \sqrt{(300)^{2} + (400)^{2}} = 500 Ω$

$i = \frac{200}{500} = 0.4 A$