A 30cm high bucket is completely filled with a liquid. A coin at the bottom appears to be raised by 12cm. The refractive index of the liquid is

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1.33

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1.67

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1.25

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Solution

The correct option is C 1.67
$A p p a r e n t D e p t h = \frac{A c t u a l D e p t h}{n_{12}} Medium 1= liquid (n) Medium 2 = air (1) n_{l a} = \frac{n l}{1} = n 18 = \frac{30}{n} \Rightarrow n = \frac{30}{18} n = \frac{5}{3} = 1.67$

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A 30cm high bucket is completely filled with a liquid. A coin at the bottom appears to be raised by 12cm. The refractive index of the liquid is

The correct option is C 1.67Apparent Depth=Actual Depthn12Medium 1= liquid (n)Medium 2 = air (1)nla=nl1=n18=30n⇒ n=3018n=53=1.67

The correct option is C 1.67
$A p p a r e n t D e p t h = \frac{A c t u a l D e p t h}{n_{12}} Medium 1= liquid (n) Medium 2 = air (1) n_{l a} = \frac{n l}{1} = n 18 = \frac{30}{n} \Rightarrow n = \frac{30}{18} n = \frac{5}{3} = 1.67$