1
Question
A 32-digit number has all 9’s. Find the remainder when the number is divided by 111.
Open in App
Solution
The correct option is D 99
option d
Any number of the form aaa (3 digits) or aaaaaa (multiple of 3 digits, i.e. 6, 9 .....) is divisible by 111
Therefore group the above numbers into groups of 3 or multiples of 3.
A 32 digit number can be broken up as (3*10 digits) + (2 digits). The first part is divisible by 111. the last two digits will thus be the remainder = 99
option d
Any number of the form aaa (3 digits) or aaaaaa (multiple of 3 digits, i.e. 6, 9 .....) is divisible by 111
Therefore group the above numbers into groups of 3 or multiples of 3.
A 32 digit number can be broken up as (3*10 digits) + (2 digits). The first part is divisible by 111. the last two digits will thus be the remainder = 99
Suggest Corrections
0
Similar questions
View More
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program
