$a^{36} + a^{36}$ is exactly divisible by

a - b

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a + b

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a^{2} - b^{2}

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None

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Solution

The correct option is C None
$a^{36} + a^{36} = 2 a^{36}$
Option D is true.

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Similar questions

a^{36} - b^{36}

(1 + x^{2}) = a_{0} + a_{1} x + a_{2} x^{2} + . . . . + a_{36} x^{36}

a_{0} + a_{3} + a_{6} + . . . + a_{36} = \frac{2}{3} (2^{35} + 1)

a_{0} + a_{1} + a_{2} + . . . + a_{36} = 2^{36}

a_{0} + a_{2} + a_{4} + . . . + a_{36} = 2^{35}

{(1 + x)}^{36} = a_{0} + a_{1} x + a_{2} x^{2} + . . . a_{36} x^{36}

a_{0} + a_{3} + a_{6} + . . . . + a_{36}

A

A 36 - 1 A 4 = 742

Simplify $\frac{a - b}{a} + \frac{a + b}{b}$

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