You visited us 2 times! Enjoying our articles? Unlock Full Access!

Raoult's Law

A3B2 is a spa...

Question

$A_{3} B_{2}$ is a sparingly soluble salt of molar mass $M g m o l^{- 1}$ and solubility $x g l i t r e^{- 1}$ . The ratio of molar concentration of $B^{3 -}$ to the solubility of the salt is:

3 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2 : 1$
The solubility of the salt $A_{3} B_{2}$ is x g/L. Its molar solubility will be $\frac{x}{M} m o l / L$ .
The molar solubility of $B^{3 -}$ ion will be $\frac{2 x}{M} m o l / l i t$
The ratio of molar concentration of $B^{3 -}$ to the solubility of the salt is $\frac{\frac{2 x}{M} m o l / L}{\frac{x}{M} m o l / L} = 2 : 1$

Suggest Corrections

Similar questions

A_{3} B_{2}

is a sparingly soluble salt of molar mass M (

{g m o l}^{- 1})

and solubility x g litre

^{- 1}

. The ratio of the molar concentration of

B^{3 -}

to the solubility product of the salt is :

$A_{3} B_{2}$ is a sparingly soluble salt of molar mass M $(g m o l^{- 1})$ and solubility x g $L^{- 1}$ . The solubility product satisfies $K_{S P} = a {(\frac{x}{M})}^{5}$ . The vlaue of a is ______(Integer answer).

Q. The molar solubility (in

m o l {l i t r e}^{- 1}

) of a sparingly soluble salt

M X_{4}

S

. The corresponding solubility product

K_{s p}

is given by the relation:

Q. The molar solubility in

(m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} s^{'}

.The molar solubility product is

K_{s p}

^{'} s^{'}

is given in terms of

K_{s p}

by the relation:

Q. The molar solubility (in

m o l L^{- 1})

of a sparingly soluble salt

M X_{4}

^{'} S^{'}

. The corresponding solubility product is

^{'} K_{s p}^{'}

^{'} S^{'}

in term of

^{'} K_{s p}^{'}

is given by the relation:

Join BYJU'S Learning Program

A3B2 is a sparingly soluble salt of molar mass M g mol−1 and solubility x g litre−1. The ratio of molar concentration of B3− to the solubility of the salt is:

The correct option is C 2:1The solubility of the salt A3B2 is x g/L. Its molar solubility will be xMmol/L.The molar solubility of B3− ion will be 2xMmol/litThe ratio of molar concentration of B3− to the solubility of the salt is 2xMmol/LxMmol/L=2:1

$A_{3} B_{2}$ is a sparingly soluble salt of molar mass $M g m o l^{- 1}$ and solubility $x g l i t r e^{- 1}$ . The ratio of molar concentration of $B^{3 -}$ to the solubility of the salt is: