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Raoult's Law

A3B2 is a spa...

Question

$A_{3} B_{2}$ is a sparingly soluble salt of molar mass $M g m o l^{- 1}$ and solubility $x g l i t r e^{- 1}$ . The ratio of molar concentration of $B^{3 -}$ to the solubility of the salt is:

3 : 1

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2 : 3

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2 : 1

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none of these

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Solution

The correct option is C $2 : 1$
The solubility of the salt $A_{3} B_{2}$ is x g/L. Its molar solubility will be $\frac{x}{M} m o l / L$ .
The molar solubility of $B^{3 -}$ ion will be $\frac{2 x}{M} m o l / l i t$
The ratio of molar concentration of $B^{3 -}$ to the solubility of the salt is $\frac{\frac{2 x}{M} m o l / L}{\frac{x}{M} m o l / L} = 2 : 1$

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