Question

A $4.00\mu F$ capacitor and a $6.00\mu F$ capacitor are connected in parallel across a $660V$supply line. Find the charge on each capacitor and the voltage across each of them.

Answer 1

As the both capacitor are in parallel so potential across them will be same i.e $660V$.

Now using $Q=CV$, the charge on $4\mu F$ is $Q_1=(4\times {10}^{-6})\times 660=2.64\times {10}^{-3}C$ and the charge on $6\mu F$ is $Q_2=(6\times {10}^{-6})\times 660=3.96\times {10}^{-3}C$