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Dalton's Law of Partial Pressures

A 4:1 molar...

Question

A $4 : 1$ molar mixture of He and $C H_{4}$ is connected in a vessel at $20$ bar pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture leaking out?

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Solution

Molar ratio = 1:4
Total pressure = 20
Hence Partial pressure ratio = 16 : 4
$\frac{n_{H e}}{n_{C H_{4}}} = \frac{P_{H e}}{P_{C H_{4}}} \times \sqrt{\frac{M_{C H_{4}}}{M_{H e}}}$
$\frac{n_{H e}}{n_{C H_{4}}} =$ 8:1
Hence, The composition of mixture = 8:1

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