A 4.5kg object is sliding along a horizontal surface that exerts friction on the object with coefficient of friction μ=0.24 on the object. The object slides through a distance of 3.00m. What is the work performed on the object?
A
3.24J
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B
10.6J
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C
31.8J
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D
132.4J
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E
None of the above
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Solution
The correct option is C31.8J Given : m=4.5 kg μ=0.24S=3.00 m
Magnitude of frictional force f=μmg=0.24×4.5×9.8=10.58 N
Magnitude of work done W=|f×S|=|10.58×3.00|=31.8 J