Question

A 4-hour unit hydrograph of a basin can be approximated as a triangle with a base period of 48 hours and peak ordinate of $300{\text{m}}^3/\text{s}$. What is the area of the catchment basin?

• A. $7776{\text{km}}^2$
• B. $5184{\text{km}}^2$
• C. $2592{\text{km}}^2$
• D. $1294{\text{km}}^2$

Answer 1

The correct option is C $2592{\text{km}}^2$

$\frac{Q_p{T}_B}{2}=A\times \frac{1}{100}$

$A=\frac{300\times 48\times 3600\times 100}{2\times {10}^6}$

$=\frac{3\times 48\times 36}{2}=2592{\text{km}}^2$