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Question

A 4 kg projectile is launched from a height of 2 m with an initial speed of 12 m/s. Find its speed when it is at a maximum height of 3 m above the ground.


A

31 ms1

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B

231 ms1

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C

331 ms1

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D

431 ms1

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Solution

The correct option is B

231 ms1


Given, mass =4 kg

Let initial speed be u =12 m/s

Final speed at a height of 3 m be v

Initial height, h1=2m

Final height, h2=3m

According to law of conserration of energy

Initial kinetic energy + Initial potential energy =Finalkinetic energy+Final potential energy

12mu2+mgh1=12mv2+mgh2

(12)22+10×2=12×v2+10×3

72+20=v22+30

v22=62

v=124ms1=231ms1

Hence, speed at height 3 m is 231ms1.


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