Question

# A 4 m long rod of negligible weight is supported at a point 125 cm from its one end and a load of 18 kgf is suspended at a point 60 cm from the support on the shorter arm. (a) if a weight W is placed at a distance of 250 cm from the support on the longer arm, find W. (b) If a weight 5 kgf is kept to balance the rod, find the position. (c) To which class of lever does it belong?

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Solution

## Total length of rod = 4 m = 400 cm (a) 15 kgf load is placed at 60 cm from the support. W kgf weight is placed at 250 cm from the support. By the principle of moments, 18×60=W×250W=4.32 kgf (b) Given W = 5 kgf 18 kgf load is placed at 60 cm from the support. Let 5 kgf is placed at d cm from the support. By the principle of moments, 18×60=5×dd=216 cm d = 216 cm from the support on the long arm. (c) It belongs to the class I lever.

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