A 4 m long wire of resistance 8- is connected in series with a batterry of e-m-f- 2V and a resistor of 7- The internal resistance of the battey is 1- What is the potential gradient along the wire-

The e.m.f of the driver cell of a potentiometer is $2 V$ and its internal resistance is negligible. The length of the potentiometer wire is $100 c m$ and resistance is $5 Ω$ . How much resistance is to be connected in series with the potentiometer wire to have a potential gradient of $0.05 m V {c m}^{- 1}$ ?

Q. A

10 m

long wire of resistance

15

ohm is connected in series with a battery of emf

2 V

(no internal resistance) and a resistance of

5

ohm. The potential gradient along the wire is:

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A 4m long wire of resistance 8Ω is connected in series with a batterry of e.m.f. 2V and a resistor of 7Ω. The internal resistance of the battey is 1Ω. What is the potential gradient along the wire?

The correct option is B 0.25Vm−1Current flow in the potentionmeter circuit is I=28+7+1=(1/8)AVoltage drop across potentionmeter wire is Vw=(1/8)×8=1VThus, potential gradient of potentionmeter wire=Vwl=14=0.25Vm−1

A $4 m$ long wire of resistance $8 Ω$ is connected in series with a batterry of e.m.f. $2 V$ and a resistor of $7 Ω$ . The internal resistance of the battey is $1 Ω$ . What is the potential gradient along the wire?