A 4 μF capacitor is given 20 μC charge and is connected with an uncharged capacitor of capacitance 2 μF as shown in figure. When switch S is closed –
Charge flown through the battery is 203 μC
Work done by the battery is 2003 μJ
20+x4+x2−10=0
3x4=5; x=203μC
Work done by battery =x×10=2003μ C