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Question

A 4 μF capacitor is given 20 μC charge and is connected with an uncharged capacitor of capacitance 2 μF as shown in figure. When switch S is closed –


A

Charged flown through the battery is 403 μC

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B

Charge flown through the battery is 203 μC

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C

Work done by the battery is 2003 μJ

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D

Work done by the battery is 1003 μJ

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Solution

The correct options are
B

Charge flown through the battery is 203 μC


C

Work done by the battery is 2003 μJ


20+x4+x210=0

3x4=5; x=203μC

Work done by battery =x×10=2003μ C


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