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Intersection

A =4 n -3 n -...

Question

$A = {(4^{n} - 3 n - 1) | n \in N},$ $B = {9 (n - 1) | n \in N},$ then $A \cap B$ is

A

A

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B

B

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C

N

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D

ϕ

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Solution

The correct option is A $A$
$A = {0, 9, 54, . . .} B = {0, 9, 18, 27, . . .} \Rightarrow A \cap B = A$

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Similar questions

A = {4^{n} - 3 n - 1 : n \in N}

B = {9 (n - 1) : n \in N}

A = {(4^{n} - 3 n - 1) | n \in N},

B = {9 (n - 1) | n \in N},

A \cap B

X = {4^{n} - 3 n - 1; n \in R}

Y = {9 (n - 1); n \in N}

X \cap Y =

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If $X = {4^{n} - 3 n - 1 : n \in N}$ and $Y = {9 (n - 1) : n \in N},$ then show that $X \cap Y = X .$

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