A 40kg child makes 10 revolutions in 29.3 seconds, moving on a circular path. The radius of the path taken by the child is 2.9 meters. Then, centripetal force acting on him is:
A
5.32N
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B
53.2N
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C
533.6N
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D
267N
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Solution
The correct option is C533.6N Given, m=40kg and Radius of circular path(r) = 2.9m Time taken to complete 1 revolution i.e ′T′=29.310=2.93s T=2πω⇒ω=2πT
Now speed of boy v=rω=2πrT=2×3.14×2.92.93=6.22m/s
To find centripetal acceleration, applying the formula: ac=v2r=(6.22)22.9=13.34m/s2 ∴Fcentripetal=m×ac ⇒Fc=40×13.34=533.6N