Question

A 40 mm diameter shaft is subjected to a twisting moment $M_t$. If shear stress developed in shaft is $5N/m{m}^2$, what is the value of the twisting moment?

• A. 628.8 N-m
• B. 328.4 N-m
• C. 62.8 N-m
• D. 30.4 N-m

Answer 1

The correct option is C 62.8 N-m

Shear stress due to torsion will be

${\tau }_{max}=\frac{16M_t}{\pi D^3}$

$\Rightarrow M_t=\frac{5\times \pi \times (40{)}^3}{16\times {10}^3}$

$\Rightarrow M_t=62.8N-m$