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Question

A 40 μF capacitor is connected to a 200 V,50 Hz AC supply. The RMS value of the current in the circuit is nearly

A
2.5 A
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B
25.1 A
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C
1.7 A
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D
2.05 A
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Solution

The correct option is A 2.5 A
The impedance of the capacitor is given by:
Xc=12πfC
Irms=VXc
Irms=200×2×π×50×40×106
Irms=2.5 A

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