Question

A $400mg$ iron capsule contain $100mg$ of ferrous fumarate,$(CHCOO{)}_{2}Fe$. The percentage of it is approximately:

• A. $33\%$
• B. $25\%$
• C. $14\%$
• D. $8\%$

Answer 1

Answer: (D)

$8\%$

Molecular mass of $(CHCOO{)}_{2}Fe=170$

$\%$ of $Fe$ is capsule $=\frac{56}{170}\times \frac{100}{900}\times 100\%$

$\%$ of $Fe$ in capsule $=\frac{56}{170}\times \frac{100}{900}\times 100\%$

$=8\%$