Question

A $40kgm$ slab rests on a frictionless floor. A $10kg$ block rests on the top of the slab. The static coefficient of friction between the block and the slab is $0.60$ while the kinetic friction is $0.40$. The $10kg$ block is acted upon by a horizontal force of $100N$. If $g=9.8m/s^2$

Answer 1

As per given

(1) Maximum static friction force :

$(F_{rs}{)}_{max}$ = ${\mu }_s\times R$ {R = Reaction force; R=mg}

$(F_{rs}{)}_{max}$ = 0.6 $\times 10\times 10$

= 60 N

(2) Kinetic friction force :

$F_{rk}$ = ${\mu }_k\times R$

= 0.4 $\times 10\times 10$

= 40 N