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Question

A 40mL sample of 0.1M solution of nitric acid is added to 20mL of 0.3M aqueous ammonia. What is the pH of the resulting solution? Given, Kb for ammonia 1.8×105.

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Solution

HNO3+NH4OHNH4NO3+H2O
4millimol 6millimol
2millimol 4millimol
(Weak base) and (salt of weak base and strong acid) will form basic buffer.
So pOH=pKb+log[Salt][Base]
pOH=5log(1.8)+log42
pOH=4.96
As we know that pH+pOH=14
pH=9.04

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