A $4 c m$ cube is cut into $1 c m$ cubes. Calculate the total surface area of all the small cubes. (in ${c m}^{2}$ )

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Solution

Number of $1 c m$ cubes cut from a $4 c m$ cube $= \frac{v o l u m e o f 4 c m c u b e}{v o l u m e o f 1 c m c u b e} = \frac{4^{3}}{1^{3}} = 64$
$∴$ TSA of $64, 1 c m$ cubes $= 64 \times 6 \times 1^{2} {c m}^{2} = 384 {c m}^{2}$

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Question 2

A cube of side 4 cm is cut into 1 cm cubes. What is the ratio of the surface areas of the original cube and cut-out cubes ?
(a) 1 : 2 (b) 1 :3 (c) 1 : 4 (d) 1 : 6

Q. A

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1 c m

cubes. Calculate the total surface area of all the small cubes.

A cube of side 4 $c m$ is cut into cubes of side 1 $c m$ . Calculate the total surface area of all the small cubes.

Q. 18. A big cube of 4cm is cut into 1cm cubes. Calculate the TSA of all the small cubes. Also find the ratio of summer of of TSA of small cubes to the TSA of the big cube

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A 4cm cube is cut into 1cm cubes. Calculate the total surface area of all the small cubes. (in cm2)

Number of 1cm cubes cut from a 4cm cube =volumeof4cmcubevolumeof1cmcube=4313=64∴ TSA of 64,1cm cubes =64×6×12cm2=384cm2

A $4 c m$ cube is cut into $1 c m$ cubes. Calculate the total surface area of all the small cubes. (in ${c m}^{2}$ )

Number of $1 c m$ cubes cut from a $4 c m$ cube $= \frac{v o l u m e o f 4 c m c u b e}{v o l u m e o f 1 c m c u b e} = \frac{4^{3}}{1^{3}} = 64$
$∴$ TSA of $64, 1 c m$ cubes $= 64 \times 6 \times 1^{2} {c m}^{2} = 384 {c m}^{2}$