A 5.0 cm long straight piece of thread is kept on the surface of water. Find the force with which the surface on one side of the thread pulls it. Surface tension of water = $0.076 N m^{- 1}$ .

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Solution

L = 5 cm = $5 \times 10^{- 2} m$

T = 0.76 N/m

F = $T_{1} = 0.76 \times 5 \times 10^{2}$

= $3.8 \times 10^{- 3} N$ .

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A 5.0 cm long straight piece of thread is kept on the surface of water. Find the force with which the surface on one side of the thread pulls it. Surface tension of water = 0.076Nm−1.

L = 5 cm = 5×10−2m T = 0.76 N/m F = T1=0.76×5×102 = 3.8×10−3N.

A 5.0 cm long straight piece of thread is kept on the surface of water. Find the force with which the surface on one side of the thread pulls it. Surface tension of water = $0.076 N m^{- 1}$ .

L = 5 cm = $5 \times 10^{- 2} m$

T = 0.76 N/m

F = $T_{1} = 0.76 \times 5 \times 10^{2}$

= $3.8 \times 10^{- 3} N$ .