Question

A $5.0$ mL solution of $H_2{O}_2$ liberates $0.508$ g of iodine from an acidified $KI$ solution. The strength of $H_2{O}_2$ solution in terms of volume strength at $STP$ will be :

• A. $2.24V$
• B. $4.48V$
• C. $8.96V$
• D. none of the above

Answer 1

The correct option is B $4.48V$

Milliequivalents of $I_2=\frac{0.508}{127}\times 1000$

Milliequivalents of $KI=\frac{0.508}{127}\times 1000$

Milliequivalents of $H_2{O}_2=\frac{0.508}{127}\times 1000$

Normality of $H_2{O}_2=\frac{0.508}{127}\times \frac{1000}{5}$

For $H_2{O}_2$, $5.6\times$ Normality $=$ Volume strength

$\therefore$ Volume strength $=\frac{0.508}{127}\times \frac{1000}{5}\times 5.6=4.48V$