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Question

A 5.0 kg block moves in a straight line on a horizontal frictionless surface under the influence of a force that varies with position as shown in figure. How much work done by the force as the block moves from the origin to x=8 m?


A
30 J
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B
16 J
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C
46 J
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D
14 J
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Solution

The correct option is D 14 J
Work done = area under graph=area of region I + area of region II + area of region III
W=2×10+12×2×1012×4×8W=20+1016W=14 J

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