A 5.0kg block moves in a striaght line on a horizontal frictionless surface under the influence of a force that varies with position as shown in figure. How much work done by the force as the block moves from the origin to x=8m?
A
30J
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B
16J
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C
46J
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D
14J
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Solution
The correct option is D14J Work done = area under graph=area of region I + area of region II + area of region III W=2×10+12×2×10−12×4×8W=20+10−16W=14J