Question

A $5.0A$ current is setup in an external circuit by a $6.0V$ storage battery for $6.0$ min. The chemical energy of the battery is reduced by

• A. $1.08\times {10}^{4}J$
• B. $1.08\times {10}^{-4}J$
• C. $1.8\times {10}^{4}J$
• D. $1.8\times {10}^{-4}J$

Answer 1

The correct option is A $1.08\times {10}^{4}J$

Given : $V=6.0$ volts $I=5.0$ A

Time for which current flows, $t=6\times 60=360$ s

Electric power spent by the battery $P=VI$

$\Rightarrow P=6\times 5=30Wor30J/s$

Electric energy spent by the battery $E=Power\times time$

$\therefore$ $E=30J/s\times 360s=1.08\times {10}^4$ $J$

This electric energy came from the chemical energy stored within the battery.

So the energy of the battery is reduced by $1.08\times {10}^{4}J.$