A $5.0 g$ sample of a pure compound containing $H, C$ , and $N$ contains $0.19 g$ of $H$ and $2.22 g$ of $C$ . Another smaller sample of this pure compounds is analyzed.
How many grams of $N$ should be found in the new $2.0 g$ pure sample?

0.65 g

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1.0 g

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6.5 g

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More information is needed to determine.

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Solution

The correct option is C $1.0 g$
Given, Mass of sample $= 5 g;$
Mass of $C$ in sample $= 2.22 g$
Mass of $H$ in sample $= 0.19 g$
Mass of Nitrogen $= 5 - (2.22 + 0.19) = 2.57 g$
Percentage of Nitrogen $= \frac{2.57}{5} \times 100 = 51.4 %$
Mass of Nitrogen in $2 g$ sample $= (\frac{51.4}{100} \times 2) = 1.02 g$

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A 5.0g sample of a pure compound containing H,C, and N contains 0.19g of H and 2.22g of C. Another smaller sample of this pure compounds is analyzed.How many grams of N should be found in the new 2.0g pure sample?

The correct option is C 1.0 gGiven, Mass of sample =5 g; Mass of C in sample =2.22 gMass of H in sample =0.19 gMass of Nitrogen =5−(2.22+0.19)=2.57 gPercentage of Nitrogen =2.575×100=51.4%Mass of Nitrogen in 2 g sample =(51.4100×2)=1.02 g

A $5.0 g$ sample of a pure compound containing $H, C$ , and $N$ contains $0.19 g$ of $H$ and $2.22 g$ of $C$ . Another smaller sample of this pure compounds is analyzed.
How many grams of $N$ should be found in the new $2.0 g$ pure sample?