The correct option is B 210.0 g mol^ 1 Since the 2 solutions are isotonic : ⇒ C_1=C_2 ⇒5 25M=1.560 #160; #160; #160; #160;[ ∴ D ...

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Standard XII

Chemistry

Molality

A 5.25

Question

A $5.25$ solution of a substance is isotonic with a $1.5 %$ solution of urea (molar mass = $60 g m o l^{- 1})$ in the same solvent. If the densities of both the solutions are assumed to be equal to $1.0 g c m^{- 3}$ , molar mass of the substance will be:

105.0 g m o l^{- 1}

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210.0 g m o l^{- 1}

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90.0 g m o l^{- 1}

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15.0 g m o l^{- 1}

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Solution

The correct option is B $210.0 g m o l^{- 1}$
Since the 2 solutions are isotonic :
$\Rightarrow C_{1} = C_{2}$
$\Rightarrow \frac{5 - 25}{M} = \frac{1.5}{60}$ [ $∴$ Densities are equal, volume can be ignored ]
$∴ M = 210 g / m o l .$
Hence, the answer is $210 g / m o l .$

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A 5.25 solution of a substance is isotonic with a 1.5% solution of urea (molar mass = 60gmol−1) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0gcm−3, molar mass of the substance will be:

The correct option is B 210.0gmol−1Since the 2 solutions are isotonic :⇒C1=C2⇒5−25M=1.560 [ ∴ Densities are equal, volume can be ignored ]∴M=210g/mol.Hence, the answer is 210g/mol.

A $5.25$ solution of a substance is isotonic with a $1.5 %$ solution of urea (molar mass = $60 g m o l^{- 1})$ in the same solvent. If the densities of both the solutions are assumed to be equal to $1.0 g c m^{- 3}$ , molar mass of the substance will be:

The correct option is B $210.0 g m o l^{- 1}$
Since the 2 solutions are isotonic :
$\Rightarrow C_{1} = C_{2}$
$\Rightarrow \frac{5 - 25}{M} = \frac{1.5}{60}$ [ $∴$ Densities are equal, volume can be ignored ]
$∴ M = 210 g / m o l .$
Hence, the answer is $210 g / m o l .$