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Question

A(5,4),B(−3,−2) and C(1,−8) are the vertices of a triangle ABC. The respective equations of the median AD and the line l parallel to AC passing through point B are

A
3x+2y7=0 & 3x+y+7=0
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B
3x2y+7=0 & 3xy+7=0
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C
3x2y7=0 & 3xy+7=0
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D
3x+2y7=0 & 3xy7=0
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Solution

The correct option is C 3x2y7=0 & 3xy+7=0
At first for median through A ie, AD, D=(1,5){mid point of BC}
Equation of AD : y+5=32(x+1)
3x2y=7
Now, line from B parallel To AC would be, B=(3,2),m=mAC=124=3
Eq:y+2=3(x+3)
3xy+7=0

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