Question

$A(5,4),B(-3,-2)$ and $C(1,-8)$ are the vertices of a triangle ABC. Find the equation of median AD and line parallel to AB passing through the point C.

Answer 1

Given that the vertices of a triangle are $A(5,4)$ , $B(-3,-2)$ and $C(1,-8)$

The midpoint of $BC$ is $D(-1,-5)$

The equation of median $AD$ is $(y-4)=\frac{3}{2}(x-5)$

$\Rightarrow 3x-2y-7=0$

The slope of line which is parallel to $AB$ is $\frac{3}{4}$

The equation of line parallel to $AB$ and passing through $C$ is $(y+8)=\frac{3}{4}(x-1)$

$\Rightarrow 3x-4y-35=0$