A (5, 4), B (-3, -2) and C (1, -8) are the vertices of a triangle ABC. Find :
(i) the slope of the altitude of AB,
(ii) the slope of the median AD and
(iii) the slope of the line parallel to AC.
Given, A (5, 4), B (-3, -2) and C (1, -8) are the vertices of a triangle ABC.
(i) Slope of AB =
Slope of the altitude of AB =
(ii) Since, D is the mid-point of BC.
Co-ordinates of point D are
Slope of AD =
(iii) Slope of AC =
Slope of line parallel to AC = Slope of AC = 3