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Photosynthesis

A 5g mixtur...

Question

A $5$ g mixture of $S O_{2}$ and $O_{2}$ gases is reacted to form $S O_{3}$ gas. What should be the mass ratio of $S O_{2}$ and $O_{2}$ gases in mixture to obtain maximum amount of $S O_{3}$ gas.

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Solution

$2 S O_{2} + O_{2} \to S O_{3}$
Molar mass of $S O_{3} = 80$
Molar mass of $O_{2} = 32$
So 1 gram $S O_{3}$ react with 32/80m gram of oxygen
Therefore 5 gram $S O_{3}$ react with $32 / 80 \times 80 = 2$ gram oxygen
So Their mass ratio is $\frac{S O_{3}}{O_{2}} = \frac{5}{3}$

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