Question

A 5 g piece of ice at −20∘C is put into 10 g of water at 30∘C. Assuming that heat is exchanged only between the ice and the water, find the final temperature of the mixture. Specific heat capacity of ice = 2100 J kg−1∘C−1, specific heat capacity of water = 4200 J kg−1∘C−1 and latent heat of fusion of ice = 3.36 × 105 J kg−1.

- 10°C

- 5°C

20°C

0°C

Solution

The correct option is **D**

0°C

The heat given by the water when it cools down from 30∘C to 0∘C is

(0.01 kg) (4200 J kg−1∘C−1) (30∘C) = 1260 J.

The heat required to bring the ice to 0∘C is

(0.005 kg) (2100 J kg−1∘C−1) (20∘C) = 210 J.

The heat required to melt 5g of ice is

(0.005 kg)(3.36 × 105 J kg−1) (20∘C) = 1680 J.

We see that whole of the ice cannot be melted as the required amount of heat is not provided by the water. Also, the heat is enough to bring the ice to 0∘C. Thus the final temperature of the mixture is 0∘C with some of the ice melted.

Suggest corrections

0 Upvotes

Similar questions

View More...

People also searched for

View More...

- About Us
- Contact Us
- Investors
- Careers
- BYJU'S in Media
- Students Stories - The Learning Tree
- Faces of BYJU'S – Life at BYJU'S
- Social Initiative - Education for All
- BYJU'S APP
- FAQ
- Support

© 2021, BYJU'S. All rights reserved.