Question

a 5 kg ball is thrown up with a speed of 10m/s.
a) find its kinetic energy at the time of throw
b) find its potential energy when it reaches the highest point

Answer 1

Dear Student
$$\begin{gathered} velocity=10m{s}^{-1} \\ Kineticenergy=1/2m{v}^2=1/2\times 5\times 100=250J \\ whichchangestomaximumpotentialenergyatthetop \\ Potentialenergy=250Jatmaximumheight \\ Regards \end{gathered}$$