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Standard XI

Physics

Conservation of Momentum

A 5 kg block ...

Question

A 5 kg block is tied to a 1 m string and is rotated with a constant angular velocity of 2 rad/sec in the horizontal plane.Linear momentum of block is.

10 kg m/s

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5 kg m/s

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10 N

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5 N

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Solution

The correct option is A 10 kg m/s
Angular velocity $ω$ = 2 rad/sec

Radius = length of string = 1 m

Speed v = r $ω$

v = 2 m/s

Momentum = mass $\times$ speed

= 5 $\times$ 2

= 10 kg m/s

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Similar questions

A 5kg block is tied to a 1m string and is rotated with a constant angular velocity of 2 rad/sec in the horizontal plane. Find the linear momentum of the block.

Q. A 5 kg block is tied to a 1 m string and is rotated with a constant angular velocity of 2 rad/sec in the horizontal plane.Linear momentum of block is.

5

balls of mass

1 kg, 2 kg, 3 kg, 4 kg

and

5 kg

are tied in a horizontal plane with the massless rod as shown in figure. Balls are rotating about

X X^{'}

axis with constant angular velocity

ω = 10 rad/s

. Find the magnitude of angular momentum [in

{kg m}^{2} /s

] about axis

X X^{'}

5

balls of mass

1 kg, 2 kg, 3 kg, 4 kg

and

5 kg

are tied in a horizontal plane with the massless rod as shown in figure. Balls are rotating about

X X^{'}

axis with constant angular velocity

ω = 10 rad/s

. Find the magnitude of angular momentum [in

{kg m}^{2} /s

] about axis

X X^{'}

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A 5 kg block is tied to a 1 m string and is rotated with a constant angular velocity of 2 rad/sec in the horizontal plane.Linear momentum of block is.

The correct option is A 10 kg m/sAngular velocity ω = 2 rad/sec Radius = length of string = 1 m Speed v = r ω v = 2 m/s Momentum = mass × speed = 5 × 2 = 10 kg m/s

The correct option is A 10 kg m/s
Angular velocity $ω$ = 2 rad/sec

Radius = length of string = 1 m

Speed v = r $ω$

v = 2 m/s

Momentum = mass $\times$ speed

= 5 $\times$ 2

= 10 kg m/s