Question

A 5 kg box is pushed across a level floor with a force of 50 N for a displacement of 10 m. then lifted to a height of 3 m. Find out the total work done on the box?

• A. 250 J
• B. 500 J
• C. 650 J
• D. 2,500 J
• E. 7,500 J

Answer 1

Answer: (C)

650 J

Given : $F=50$ N $S=10$ m $h=3$ m $m=5kg$

Total work done $W_T=W_{push}+W_{lift}$

$\therefore$ $W_T=FS+\left(mg\right)h$

OR $W_T=50\times 10+(5\times 10)\times 3=500+150=650$ J