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Standard XII

Physics

Oblique Collision

A 5 kg mass m...

Question

A 5 kg mass moving at a speed of $13 m s^{- 1}$ collides head on with a body of mass 1 kg at rest, if they move with a common velocity after collision in the same direction, find the velocity ?

103 m s^{- 1}

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10.83 m s^{- 1}

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1.03 m s^{- 1}

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20 m s^{- 1}

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Solution

The correct option is C $10.83 m s^{- 1}$
Using momentum conservation for inelastic collision,
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v$

$v = \frac{m_{1} u_{1} + m_{2} u_{2}}{m_{1} + m_{2}}$

$v = \frac{13 \times 5}{6}$ $= 10.83 m s^{- 1}$

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A 5 kg mass moving at a speed of 13ms−1 collides head on with a body of mass 1 kg at rest, if they move with a common velocity after collision in the same direction, find the velocity ?

The correct option is C 10.83 ms−1Using momentum conservation for inelastic collision,m1u1+m2u2=(m1+m2)vv=m1u1+m2u2m1+m2v=13×56 =10.83 ms−1

A 5 kg mass moving at a speed of $13 m s^{- 1}$ collides head on with a body of mass 1 kg at rest, if they move with a common velocity after collision in the same direction, find the velocity ?

The correct option is C $10.83 m s^{- 1}$
Using momentum conservation for inelastic collision,
$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v$

$v = \frac{m_{1} u_{1} + m_{2} u_{2}}{m_{1} + m_{2}}$

$v = \frac{13 \times 5}{6}$ $= 10.83 m s^{- 1}$