A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find the cost of painting a pole that casts a shadow 5 m long. Painting is done at the rate of ₹ 5 per cm.

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Solution

The ratio of the length of the pole to the length of the shadow remains constant.

The length of pole and the length of the shadow are directly proportional

$\frac{A}{B}$ = Constant

$\frac{A_{1}}{B_{1}}$ = $\frac{A_{2}}{B_{2}}$

$\frac{L e n g t h o f p o l e}{l e n g t h o f s h a d o w} = \frac{560}{320} = \frac{n}{500} (where n is length the second pole)$

n = 875 cm

$∴$ the height of the pole = 875 cm

Cost of painting the pole = 875 x 5 = ₹ 4375

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Similar questions

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find the cost of painting a pole that casts a shadow 5 m long. Painting is done at the rate of ₹ 5 per cm.

A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find the cost of painting a pole that casts a shadow of 5 m. Painting is done at Rs.5 per cm.

Q. A

5

60

cm high vertical pole casts a shadow

3

20

cm long. Find the height of a pole which casts a shadow

5

m long at the same time.

Question 09.2 .
A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time the height of a pole which casts a shadow 5 m long.

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