Question

A $5mL$ solution of $5N{H}_{2}S{O}_4$​ is diluted to$250mL$. What will be the normality of $H_{2}S{O}_4$ in the diluted solution ?

• A. $0.6N$
• B. $0.2N$
• C. $0.5N$
• D. $0.1N$

Answer 1

The correct option is D $0.1N$

The formula is -
$N_1{V}_1=N_2{V}_2$

$N_{1}of{H}_{2}S{O}_4=5N$
$V_{1}of{H}_{2}S{O}_4=5mL$
$N_{2}of{H}_{2}S{O}_4=?$
$V_{2}of{H}_{2}S{O}_4=250mL$

So,
putting the values,
$N_2=\frac{5\times 5}{250}$
$N_2=0.1N$