wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A 5μF capacitor is charged to 12 V. The positive plate of the capacitor is connected to the negative terminal of a 12 V battery and vice versa. Find the heat developed in the connecting wires :

A
72μJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
720μJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1.44μJ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
144μJ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 1.44μJ
The capacitor is connected to the battery so its potential remains constant. As they are connected in opposite polarity so potential across capacitor is V=12+12=24V
Here the stored energy in capacitor will develop heat in the connecting wires.
Thus, the heat, H=U=12CV2=0.5×5×106×242=1.44μJ

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Capacitance of a Parallel Plate Capacitor
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon