A 5% solution of a cane sugar has freezing point of 271 k. Calculate the freezing point of a 5% glucose in water if freezing point of pure water is 273.15 kelvin

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Q. A 5 % solution ( by mass ) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5 % glucose in water if freezing point of pure water is 273.15 K.

QUESTION 2.20

A $5 %$ solution (by mass) of cane sugar in water has freezing point 271 K. Calculate freezing point of $5 %$ glucose in water if freezing point of pure water is 273.15K.

Q. A

5

% solution (by mass) of cane sugar in water has freezing point of

271 K

and freezing point of pure water is

273.15 K

. The freezing point of a

5

% solution (by mass) of glucose in water is :

Q. A

5

% solution (w/W) of cane sugar (molar mass

= 342 g

{m o l}^{- 1}

) has freezing point

271 K

. What will be the freezing point of

5

% glucose (molar mass

= 18 g

{m o l}^{- 1}

) in water if freezing point of pure water is

273.15 K

Q. A 4% solution(w/w) of sucrose (M = 342

g m o l^{- 1})

in water has a freezing point of 271.15 K. Calculate the freezing point of 5% glucose (M = 180

g m o l^{- 1})

in water. (Given: Freezing point of pure water = 273.15 K)

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