The area of a triangle is 5. Two of its vertices are (2, 1) and (3, -2). The third vertex lies on $y = x + 3$ . Find the coordinates of the third vertex.

Q. The area of a triangle is

5

square units. Two of its vertices are

(2, 1)

and

(3, - 2)

. The third vertex lies on

y = x + 3

. The third vertex is

The area of the triangle whose vertices are (2, 3), (3, 5) and (7, 5) is:

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A(−5,0) and B(3,0) are two of the vertices of a triangle ABC. Its area is 20 square cms. The vertex C lies on the line x−y=2. The coordinates of C are

The correct option is B (−3,−5) or (7,5)Let the coordinates of C be (h,k)Area of △ABC=12|8×k|⇒k=±5Since, C lies on the line x−y−2=0⇒h−k−2=0⇒h=7,−3Hence, the coordinates of C are (7,5) and (−3,−5)

$A (- 5, 0)$ and $B (3, 0)$ are two of the vertices of a triangle $A B C$ . Its area is 20 square cms. The vertex $C$ lies on the line $x - y = 2$ . The coordinates of $C$ are