A $50 c m$ long conductor AB moves with a speed $4 m / s$ in a magnetic field $B = 0.01 W b / m^{2}$ as shown. Find the emf generated and power delivered if resistance of the circuit is $0.1 Ω$ .

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Solution

Given, $l = 50 c m = 50 \times 10^{- 2} m, v = 4 m / s, B = 0.01 W b / m^{2}$ .
Motional emf
$e = v B l = 4 \times 0.01 \times 50 \times 10^{- 2} = 200 \times 10^{- 4} = 2 \times 10^{- 2} V$
Power $p = \frac{e^{2}}{R} = \frac{4 \times 10^{- 4}}{0.1} = 4 \times 10^{- 3}$

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