A 50 g bullet pierces through a plate of mass M₁ = 1 kg and then comes to rest inside a second plate of mass M₂ = 2.95 kg as shown in figure. It is found that the two plates, initially at rest, now move with equal velocities. Find the percentage loss in the initial velocity of bullet when it is between M₁ and M₂. (Neglect any loss of material of the plates due to the action of the bullet.)

50 g की एक गोली द्रव्यमान M₁ = 1 kg की प्लेट में छेद करते हुए इससे गुजरती है तथा फिर चित्रानुसार द्रव्यमान M₂ = 2.95 kg की द्वितीय प्लेट के अंदर विराम में आती है। यह पाया जाता है कि प्रारम्भ में विराम में स्थित दोनों प्लेटें अब समान वेगों से गति करती हैं। जब गोली M₁ व M₂ के मध्य हैं, तब गोली के प्रारम्भिक वेग में प्रतिशत हानि ज्ञात कीजिए। (गोली की क्रिया के कारण प्लेटों के पदार्थ में किसी भी हानि को नगण्य मानिए।)

50%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

75%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 25%
Solution

Suggest Corrections

Similar questions

Q. A

20 k g

bullet pierces through a plate of mass

M_{1} = 1 k g

and then comes to rest inside a second plate of mass

M_{2} = 2.98 k g

as shown in the figure. It is found that the two plates initially at rest and now move with equal velocities. Find the percentage loss in the initial velocity of the bullet when it is between

M_{1}

and

M_{2}

. (Neglect any loss of material of the plates due to the action of bullet).

Two block of wood of masses $m_{1}$ and $m_{2}$ and each of specific gravity 0.5 are submerged at a depth of $h_{1}$ and $h_{2}$ in
a vessel $(h_{2} > h_{1})$ filled with water, which is accelerated upwards with an acceleration $\frac{g}{2}$ . the difference in
time taken by the blocks to reach the surface, when released with zero velocity is :

The ring $M_{1}$ and block $M_{2}$ are held in the position shown in figure. Now the system is released. If $M_{1}$ $>$ $M_{2}$ find when the ring $M_{1}$ has descended along the smooth fixed vertical rod by the distance $y$ .

The ring $M_{1}$ and block $M_{2}$ are held in the position shown in figure. Now the system is released. If $M_{1}$ $>$ $M_{2}$ find $\frac{v_{1}}{v_{2}}$ when the ring $M_{1}$ has descended along the smooth fixed vertical rod by the distance $y = h$ .

The correct statement with regard to $H_{2}^{+}$ & $H_{2}^{-}$ is

Join BYJU'S Learning Program

The correct option is B 25%Solution

The correct option is B 25%
Solution