Question

A $50$ gram bead slides on a frictionless wire as shown above. At what point on the wire will the bead come to a complete stop? The initial speed at C is $\sqrt{2gh}$.

• A. Point A
• B. Point B
• C. Point C
• D. Point D
• E. Point E

Answer 1

The correct option is A Point A

$InitialspeedatA=\sqrt{2gh}totalenergyatA=\frac{1}{2}m{v}^2+mgh=2mghthebeadwillcometoastopwhereitsKEiszero\Rightarrow PE=2mgh\Rightarrow mgH=2mgh\Rightarrow H=2h$