Question

A $50-kg$ crate is being pushed across a horizontal floor by a horizontal force of $575N$. If the coefficient of sliding friction is $0.25$, what is the acceleration of the crate?

• A. Zero
• B. $1m/s^2$
• C. $3m/s^2$
• D. $6m/s^2$
• E. $9m/s^2$

Answer 1

The correct option is E $9m/s^2$

Given,

Force on crate, $F=575N$

Mass of crate, $m=50kg$

Coefficient of friction, $\mu =0.25$

From the equilibrium of forces

$ma=F-\mu mg$

$a=\frac{F-\mu mg}{m}$

$a=\frac{575-0.25\times 50\times 9.81}{50}$

$a=9.047m/s^2$

Acceleration of block is $9.047m/s^2$