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Variation of G Due to the Rotation of Earth

a 50 kg man c...

Question

a 50 kg man climbs a 10 m rope daily how many food calories is required for a single climb?

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Solution

$T h e e n e r g y r e q u i r e d t o c l i m b 10 m \sin g l e c l i m b U = m g h T h e r e f o r e U = 50 \times 10 \times 10 = 500 J = \frac{500}{4.2} = 119 . O 5 c a l$

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Variation of G Due to the Rotation of Earth

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