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Question

A 50 kg man is running at a speed of 18 km h1. If all the kinetic energy of the man can be used to increase the temperature of water from 200 C to 300 C, how much water can be heated with this energy ?


Solution

K.E. of the man = 12mV2

= (12)50×52

= 25×25 = 625 J

The amount of heat required to raise the temperature of water from 200 C to  300

= msΔθ=m×4200× (30-20)

= 4200 m 

But, 42 ×103m = 625

m = 62542×103

= 14.88 ×103 kg

= 15 g

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